20c^2+11c-3=

Solution for 20c^2+11c-3= equation:

Simplifying
20c2 + 11c + -3 = 0

Reorder the terms:
-3 + 11c + 20c2 = 0

Solving
-3 + 11c + 20c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-3 + -4c)(1 + -5c) = 0

Subproblem 1
Set the factor '(-3 + -4c)' equal to zero and attempt to solve:

Simplifying
-3 + -4c = 0

Solving
-3 + -4c = 0

Move all terms containing c to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + -4c = 0 + 3

Combine like terms: -3 + 3 = 0
0 + -4c = 0 + 3
-4c = 0 + 3

Combine like terms: 0 + 3 = 3
-4c = 3

Divide each side by '-4'.
c = -0.75

Simplifying
c = -0.75
Subproblem 2
Set the factor '(1 + -5c)' equal to zero and attempt to solve:

Simplifying
1 + -5c = 0

Solving
1 + -5c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -5c = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -5c = 0 + -1
-5c = 0 + -1

Combine like terms: 0 + -1 = -1
-5c = -1

Divide each side by '-5'.
c = 0.2

Simplifying
c = 0.2
Solution
c = {-0.75, 0.2}